Integrand size = 20, antiderivative size = 87 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=-\frac {a^5 c^4}{8 x^8}+\frac {3 a^4 b c^4}{7 x^7}-\frac {a^3 b^2 c^4}{3 x^6}-\frac {2 a^2 b^3 c^4}{5 x^5}+\frac {3 a b^4 c^4}{4 x^4}-\frac {b^5 c^4}{3 x^3} \]
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Time = 0.02 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {76} \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=-\frac {a^5 c^4}{8 x^8}+\frac {3 a^4 b c^4}{7 x^7}-\frac {a^3 b^2 c^4}{3 x^6}-\frac {2 a^2 b^3 c^4}{5 x^5}+\frac {3 a b^4 c^4}{4 x^4}-\frac {b^5 c^4}{3 x^3} \]
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Rule 76
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a^5 c^4}{x^9}-\frac {3 a^4 b c^4}{x^8}+\frac {2 a^3 b^2 c^4}{x^7}+\frac {2 a^2 b^3 c^4}{x^6}-\frac {3 a b^4 c^4}{x^5}+\frac {b^5 c^4}{x^4}\right ) \, dx \\ & = -\frac {a^5 c^4}{8 x^8}+\frac {3 a^4 b c^4}{7 x^7}-\frac {a^3 b^2 c^4}{3 x^6}-\frac {2 a^2 b^3 c^4}{5 x^5}+\frac {3 a b^4 c^4}{4 x^4}-\frac {b^5 c^4}{3 x^3} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=-\frac {a^5 c^4}{8 x^8}+\frac {3 a^4 b c^4}{7 x^7}-\frac {a^3 b^2 c^4}{3 x^6}-\frac {2 a^2 b^3 c^4}{5 x^5}+\frac {3 a b^4 c^4}{4 x^4}-\frac {b^5 c^4}{3 x^3} \]
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Time = 0.37 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.70
method | result | size |
gosper | \(-\frac {c^{4} \left (280 b^{5} x^{5}-630 a \,b^{4} x^{4}+336 a^{2} b^{3} x^{3}+280 a^{3} b^{2} x^{2}-360 a^{4} b x +105 a^{5}\right )}{840 x^{8}}\) | \(61\) |
default | \(c^{4} \left (-\frac {a^{3} b^{2}}{3 x^{6}}+\frac {3 a^{4} b}{7 x^{7}}-\frac {a^{5}}{8 x^{8}}-\frac {b^{5}}{3 x^{3}}+\frac {3 a \,b^{4}}{4 x^{4}}-\frac {2 a^{2} b^{3}}{5 x^{5}}\right )\) | \(62\) |
norman | \(\frac {-\frac {1}{8} a^{5} c^{4}-\frac {1}{3} b^{5} c^{4} x^{5}+\frac {3}{4} a \,b^{4} c^{4} x^{4}-\frac {2}{5} a^{2} b^{3} c^{4} x^{3}-\frac {1}{3} a^{3} b^{2} c^{4} x^{2}+\frac {3}{7} a^{4} b \,c^{4} x}{x^{8}}\) | \(75\) |
risch | \(\frac {-\frac {1}{8} a^{5} c^{4}-\frac {1}{3} b^{5} c^{4} x^{5}+\frac {3}{4} a \,b^{4} c^{4} x^{4}-\frac {2}{5} a^{2} b^{3} c^{4} x^{3}-\frac {1}{3} a^{3} b^{2} c^{4} x^{2}+\frac {3}{7} a^{4} b \,c^{4} x}{x^{8}}\) | \(75\) |
parallelrisch | \(\frac {-280 b^{5} c^{4} x^{5}+630 a \,b^{4} c^{4} x^{4}-336 a^{2} b^{3} c^{4} x^{3}-280 a^{3} b^{2} c^{4} x^{2}+360 a^{4} b \,c^{4} x -105 a^{5} c^{4}}{840 x^{8}}\) | \(76\) |
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none
Time = 0.22 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.86 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=-\frac {280 \, b^{5} c^{4} x^{5} - 630 \, a b^{4} c^{4} x^{4} + 336 \, a^{2} b^{3} c^{4} x^{3} + 280 \, a^{3} b^{2} c^{4} x^{2} - 360 \, a^{4} b c^{4} x + 105 \, a^{5} c^{4}}{840 \, x^{8}} \]
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Time = 0.22 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.92 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=\frac {- 105 a^{5} c^{4} + 360 a^{4} b c^{4} x - 280 a^{3} b^{2} c^{4} x^{2} - 336 a^{2} b^{3} c^{4} x^{3} + 630 a b^{4} c^{4} x^{4} - 280 b^{5} c^{4} x^{5}}{840 x^{8}} \]
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Time = 0.21 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.86 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=-\frac {280 \, b^{5} c^{4} x^{5} - 630 \, a b^{4} c^{4} x^{4} + 336 \, a^{2} b^{3} c^{4} x^{3} + 280 \, a^{3} b^{2} c^{4} x^{2} - 360 \, a^{4} b c^{4} x + 105 \, a^{5} c^{4}}{840 \, x^{8}} \]
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Time = 0.27 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.86 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=-\frac {280 \, b^{5} c^{4} x^{5} - 630 \, a b^{4} c^{4} x^{4} + 336 \, a^{2} b^{3} c^{4} x^{3} + 280 \, a^{3} b^{2} c^{4} x^{2} - 360 \, a^{4} b c^{4} x + 105 \, a^{5} c^{4}}{840 \, x^{8}} \]
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Time = 0.36 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.86 \[ \int \frac {(a+b x) (a c-b c x)^4}{x^9} \, dx=-\frac {\frac {a^5\,c^4}{8}-\frac {3\,a^4\,b\,c^4\,x}{7}+\frac {a^3\,b^2\,c^4\,x^2}{3}+\frac {2\,a^2\,b^3\,c^4\,x^3}{5}-\frac {3\,a\,b^4\,c^4\,x^4}{4}+\frac {b^5\,c^4\,x^5}{3}}{x^8} \]
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